Ohio Assessments for Educators (OAE) Mathematics Practice Exam 2025 - Free Practice Questions and Study Guide

Image Description

Question: 1 / 400

For the function f(x) = √(ax + b), what is the domain?

All real numbers

All real numbers where ax + b > 0

The domain of the function \( f(x) = \sqrt{ax + b} \) is determined by the requirement that the expression inside the square root must be non-negative. This is because the square root function is only defined for non-negative numbers in the real number system.

To find the domain, you set up the inequality:

\[ ax + b \geq 0. \]

This means that we need to solve this inequality to find the values of \( x \) for which it holds true. The solution set will provide the values of \( x \) that keep the expression inside the square root non-negative, which is crucial for the output of the function to be real numbers.

Therefore, the domain of \( f(x) = \sqrt{ax + b} \) is given by the values of \( x \) that satisfy \( ax + b \geq 0 \). This requirement characterizes option B accurately, as it specifically points out that the function is defined for all real numbers where the expression \( ax + b \) is greater than or equal to zero. The other options do not appropriately reflect this fundamental requirement for defining the domain of the square root function.

Get further explanation with Examzify DeepDiveBeta

All real numbers that satisfy ax + b ≤ 0

All values of x

Next Question

Report this question

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy